Integrand size = 29, antiderivative size = 188 \[ \int \frac {(f+g x)^2}{(d+e x) \left (d^2-e^2 x^2\right )^3} \, dx=\frac {(e f+d g)^2}{32 d^4 e^3 (d-e x)^2}+\frac {f (e f+d g)}{8 d^5 e^2 (d-e x)}-\frac {(e f-d g)^2}{24 d^3 e^3 (d+e x)^3}-\frac {(e f-d g) (3 e f+d g)}{32 d^4 e^3 (d+e x)^2}-\frac {3 e^2 f^2-d^2 g^2}{16 d^5 e^3 (d+e x)}+\frac {\left (5 e^2 f^2+2 d e f g-d^2 g^2\right ) \text {arctanh}\left (\frac {e x}{d}\right )}{16 d^6 e^3} \]
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Time = 0.14 (sec) , antiderivative size = 188, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {862, 90, 214} \[ \int \frac {(f+g x)^2}{(d+e x) \left (d^2-e^2 x^2\right )^3} \, dx=\frac {\text {arctanh}\left (\frac {e x}{d}\right ) \left (-d^2 g^2+2 d e f g+5 e^2 f^2\right )}{16 d^6 e^3}+\frac {f (d g+e f)}{8 d^5 e^2 (d-e x)}-\frac {(d g+3 e f) (e f-d g)}{32 d^4 e^3 (d+e x)^2}+\frac {(d g+e f)^2}{32 d^4 e^3 (d-e x)^2}-\frac {(e f-d g)^2}{24 d^3 e^3 (d+e x)^3}-\frac {3 e^2 f^2-d^2 g^2}{16 d^5 e^3 (d+e x)} \]
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Rule 90
Rule 214
Rule 862
Rubi steps \begin{align*} \text {integral}& = \int \frac {(f+g x)^2}{(d-e x)^3 (d+e x)^4} \, dx \\ & = \int \left (\frac {(e f+d g)^2}{16 d^4 e^2 (d-e x)^3}+\frac {f (e f+d g)}{8 d^5 e (d-e x)^2}+\frac {(-e f+d g)^2}{8 d^3 e^2 (d+e x)^4}+\frac {(e f-d g) (3 e f+d g)}{16 d^4 e^2 (d+e x)^3}+\frac {3 e^2 f^2-d^2 g^2}{16 d^5 e^2 (d+e x)^2}+\frac {-5 e^2 f^2-2 d e f g+d^2 g^2}{16 d^5 e^2 \left (-d^2+e^2 x^2\right )}\right ) \, dx \\ & = \frac {(e f+d g)^2}{32 d^4 e^3 (d-e x)^2}+\frac {f (e f+d g)}{8 d^5 e^2 (d-e x)}-\frac {(e f-d g)^2}{24 d^3 e^3 (d+e x)^3}-\frac {(e f-d g) (3 e f+d g)}{32 d^4 e^3 (d+e x)^2}-\frac {3 e^2 f^2-d^2 g^2}{16 d^5 e^3 (d+e x)}-\frac {\left (5 e^2 f^2+2 d e f g-d^2 g^2\right ) \int \frac {1}{-d^2+e^2 x^2} \, dx}{16 d^5 e^2} \\ & = \frac {(e f+d g)^2}{32 d^4 e^3 (d-e x)^2}+\frac {f (e f+d g)}{8 d^5 e^2 (d-e x)}-\frac {(e f-d g)^2}{24 d^3 e^3 (d+e x)^3}-\frac {(e f-d g) (3 e f+d g)}{32 d^4 e^3 (d+e x)^2}-\frac {3 e^2 f^2-d^2 g^2}{16 d^5 e^3 (d+e x)}+\frac {\left (5 e^2 f^2+2 d e f g-d^2 g^2\right ) \tanh ^{-1}\left (\frac {e x}{d}\right )}{16 d^6 e^3} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 197, normalized size of antiderivative = 1.05 \[ \int \frac {(f+g x)^2}{(d+e x) \left (d^2-e^2 x^2\right )^3} \, dx=\frac {\frac {3 d^2 (e f+d g)^2}{(d-e x)^2}+\frac {12 d e f (e f+d g)}{d-e x}-\frac {4 d^3 (e f-d g)^2}{(d+e x)^3}+\frac {3 d^2 \left (-3 e^2 f^2+2 d e f g+d^2 g^2\right )}{(d+e x)^2}+\frac {6 d \left (-3 e^2 f^2+d^2 g^2\right )}{d+e x}+3 \left (-5 e^2 f^2-2 d e f g+d^2 g^2\right ) \log (d-e x)+3 \left (5 e^2 f^2+2 d e f g-d^2 g^2\right ) \log (d+e x)}{96 d^6 e^3} \]
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Time = 0.47 (sec) , antiderivative size = 245, normalized size of antiderivative = 1.30
method | result | size |
default | \(-\frac {-d^{2} g^{2}-2 d e f g -e^{2} f^{2}}{32 e^{3} d^{4} \left (-e x +d \right )^{2}}+\frac {\left (d^{2} g^{2}-2 d e f g -5 e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{32 d^{6} e^{3}}+\frac {f \left (d g +e f \right )}{8 d^{5} e^{2} \left (-e x +d \right )}-\frac {-d^{2} g^{2}+3 e^{2} f^{2}}{16 e^{3} d^{5} \left (e x +d \right )}-\frac {-d^{2} g^{2}-2 d e f g +3 e^{2} f^{2}}{32 e^{3} d^{4} \left (e x +d \right )^{2}}+\frac {\left (-d^{2} g^{2}+2 d e f g +5 e^{2} f^{2}\right ) \ln \left (e x +d \right )}{32 e^{3} d^{6}}-\frac {d^{2} g^{2}-2 d e f g +e^{2} f^{2}}{24 e^{3} d^{3} \left (e x +d \right )^{3}}\) | \(245\) |
norman | \(\frac {\frac {\left (11 d^{2} g^{2}+26 d e f g -31 e^{2} f^{2}\right ) x^{3}}{48 d^{4}}+\frac {\left (d^{2} g^{2}+14 d e f g +3 e^{2} f^{2}\right ) x^{2}}{16 e \,d^{3}}-\frac {e \left (d^{2} g^{2}+22 d e f g +7 e^{2} f^{2}\right ) x^{4}}{48 d^{5}}-\frac {e^{2} \left (d^{2} g^{2}+4 d e f g -2 e^{2} f^{2}\right ) x^{5}}{12 d^{6}}+\frac {\left (d^{2} g^{2}-2 d e f g +11 e^{2} f^{2}\right ) x}{16 d^{2} e^{2}}}{\left (e x +d \right )^{3} \left (-e x +d \right )^{2}}+\frac {\left (d^{2} g^{2}-2 d e f g -5 e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{32 d^{6} e^{3}}-\frac {\left (d^{2} g^{2}-2 d e f g -5 e^{2} f^{2}\right ) \ln \left (e x +d \right )}{32 d^{6} e^{3}}\) | \(251\) |
risch | \(\frac {\frac {\left (d^{2} g^{2}-2 d e f g -5 e^{2} f^{2}\right ) e \,x^{4}}{16 d^{5}}+\frac {\left (d^{2} g^{2}-2 d e f g -5 e^{2} f^{2}\right ) x^{3}}{16 d^{4}}-\frac {5 \left (d^{2} g^{2}-2 d e f g -5 e^{2} f^{2}\right ) x^{2}}{48 d^{3} e}+\frac {\left (7 d^{2} g^{2}+10 d e f g +25 e^{2} f^{2}\right ) x}{48 d^{2} e^{2}}+\frac {d^{2} g^{2}+4 d e f g -2 e^{2} f^{2}}{12 d \,e^{3}}}{\left (e x +d \right ) \left (-e^{2} x^{2}+d^{2}\right )^{2}}-\frac {\ln \left (-e x -d \right ) g^{2}}{32 d^{4} e^{3}}+\frac {\ln \left (-e x -d \right ) f g}{16 d^{5} e^{2}}+\frac {5 \ln \left (-e x -d \right ) f^{2}}{32 d^{6} e}+\frac {\ln \left (e x -d \right ) g^{2}}{32 d^{4} e^{3}}-\frac {\ln \left (e x -d \right ) f g}{16 d^{5} e^{2}}-\frac {5 \ln \left (e x -d \right ) f^{2}}{32 d^{6} e}\) | \(296\) |
parallelrisch | \(\frac {15 \ln \left (e x +d \right ) x^{5} e^{7} f^{2}-15 \ln \left (e x -d \right ) x^{5} e^{7} f^{2}+66 x \,d^{4} e^{3} f^{2}+6 \ln \left (e x +d \right ) x \,d^{5} e^{2} f g +3 \ln \left (e x -d \right ) x^{5} d^{2} e^{5} g^{2}-3 \ln \left (e x +d \right ) x^{5} d^{2} e^{5} g^{2}+3 \ln \left (e x -d \right ) x^{4} d^{3} e^{4} g^{2}-15 \ln \left (e x -d \right ) x^{4} d \,e^{6} f^{2}-3 \ln \left (e x +d \right ) x^{4} d^{3} e^{4} g^{2}+15 \ln \left (e x +d \right ) x^{4} d \,e^{6} f^{2}-6 \ln \left (e x -d \right ) x^{3} d^{4} e^{3} g^{2}+30 \ln \left (e x -d \right ) x^{3} d^{2} e^{5} f^{2}+3 \ln \left (e x -d \right ) x \,d^{6} e \,g^{2}-15 \ln \left (e x -d \right ) x \,d^{4} e^{3} f^{2}-6 \ln \left (e x -d \right ) d^{6} e f g +6 x \,d^{6} e \,g^{2}+18 x^{2} d^{3} e^{4} f^{2}+22 x^{3} d^{4} e^{3} g^{2}-62 x^{3} d^{2} e^{5} f^{2}-2 x^{4} d^{3} e^{4} g^{2}-14 x^{4} d \,e^{6} f^{2}-8 x^{5} d^{2} e^{5} g^{2}-15 \ln \left (e x -d \right ) d^{5} e^{2} f^{2}+6 x^{2} d^{5} e^{2} g^{2}-6 \ln \left (e x -d \right ) x \,d^{5} e^{2} f g +15 \ln \left (e x +d \right ) d^{5} e^{2} f^{2}+6 \ln \left (e x +d \right ) x^{3} d^{4} e^{3} g^{2}-30 \ln \left (e x +d \right ) x^{3} d^{2} e^{5} f^{2}-6 \ln \left (e x -d \right ) x^{2} d^{5} e^{2} g^{2}+30 \ln \left (e x -d \right ) x^{2} d^{3} e^{4} f^{2}+6 \ln \left (e x +d \right ) x^{2} d^{5} e^{2} g^{2}-30 \ln \left (e x +d \right ) x^{2} d^{3} e^{4} f^{2}-3 \ln \left (e x +d \right ) x \,d^{6} e \,g^{2}+15 \ln \left (e x +d \right ) x \,d^{4} e^{3} f^{2}+6 \ln \left (e x +d \right ) d^{6} e f g -12 x \,d^{5} e^{2} f g +3 \ln \left (e x -d \right ) d^{7} g^{2}-6 \ln \left (e x -d \right ) x^{5} d \,e^{6} f g +6 \ln \left (e x +d \right ) x^{5} d \,e^{6} f g +16 x^{5} e^{7} f^{2}-3 \ln \left (e x +d \right ) d^{7} g^{2}+84 x^{2} d^{4} e^{3} f g +52 x^{3} d^{3} e^{4} f g -44 x^{4} d^{2} e^{5} f g -32 x^{5} d \,e^{6} f g -6 \ln \left (e x -d \right ) x^{4} d^{2} e^{5} f g +6 \ln \left (e x +d \right ) x^{4} d^{2} e^{5} f g +12 \ln \left (e x -d \right ) x^{3} d^{3} e^{4} f g -12 \ln \left (e x +d \right ) x^{3} d^{3} e^{4} f g +12 \ln \left (e x -d \right ) x^{2} d^{4} e^{3} f g -12 \ln \left (e x +d \right ) x^{2} d^{4} e^{3} f g}{96 e^{3} d^{6} \left (e^{2} x^{2}-d^{2}\right )^{2} \left (e x +d \right )}\) | \(908\) |
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Leaf count of result is larger than twice the leaf count of optimal. 662 vs. \(2 (178) = 356\).
Time = 0.31 (sec) , antiderivative size = 662, normalized size of antiderivative = 3.52 \[ \int \frac {(f+g x)^2}{(d+e x) \left (d^2-e^2 x^2\right )^3} \, dx=-\frac {16 \, d^{5} e^{2} f^{2} - 32 \, d^{6} e f g - 8 \, d^{7} g^{2} + 6 \, {\left (5 \, d e^{6} f^{2} + 2 \, d^{2} e^{5} f g - d^{3} e^{4} g^{2}\right )} x^{4} + 6 \, {\left (5 \, d^{2} e^{5} f^{2} + 2 \, d^{3} e^{4} f g - d^{4} e^{3} g^{2}\right )} x^{3} - 10 \, {\left (5 \, d^{3} e^{4} f^{2} + 2 \, d^{4} e^{3} f g - d^{5} e^{2} g^{2}\right )} x^{2} - 2 \, {\left (25 \, d^{4} e^{3} f^{2} + 10 \, d^{5} e^{2} f g + 7 \, d^{6} e g^{2}\right )} x - 3 \, {\left (5 \, d^{5} e^{2} f^{2} + 2 \, d^{6} e f g - d^{7} g^{2} + {\left (5 \, e^{7} f^{2} + 2 \, d e^{6} f g - d^{2} e^{5} g^{2}\right )} x^{5} + {\left (5 \, d e^{6} f^{2} + 2 \, d^{2} e^{5} f g - d^{3} e^{4} g^{2}\right )} x^{4} - 2 \, {\left (5 \, d^{2} e^{5} f^{2} + 2 \, d^{3} e^{4} f g - d^{4} e^{3} g^{2}\right )} x^{3} - 2 \, {\left (5 \, d^{3} e^{4} f^{2} + 2 \, d^{4} e^{3} f g - d^{5} e^{2} g^{2}\right )} x^{2} + {\left (5 \, d^{4} e^{3} f^{2} + 2 \, d^{5} e^{2} f g - d^{6} e g^{2}\right )} x\right )} \log \left (e x + d\right ) + 3 \, {\left (5 \, d^{5} e^{2} f^{2} + 2 \, d^{6} e f g - d^{7} g^{2} + {\left (5 \, e^{7} f^{2} + 2 \, d e^{6} f g - d^{2} e^{5} g^{2}\right )} x^{5} + {\left (5 \, d e^{6} f^{2} + 2 \, d^{2} e^{5} f g - d^{3} e^{4} g^{2}\right )} x^{4} - 2 \, {\left (5 \, d^{2} e^{5} f^{2} + 2 \, d^{3} e^{4} f g - d^{4} e^{3} g^{2}\right )} x^{3} - 2 \, {\left (5 \, d^{3} e^{4} f^{2} + 2 \, d^{4} e^{3} f g - d^{5} e^{2} g^{2}\right )} x^{2} + {\left (5 \, d^{4} e^{3} f^{2} + 2 \, d^{5} e^{2} f g - d^{6} e g^{2}\right )} x\right )} \log \left (e x - d\right )}{96 \, {\left (d^{6} e^{8} x^{5} + d^{7} e^{7} x^{4} - 2 \, d^{8} e^{6} x^{3} - 2 \, d^{9} e^{5} x^{2} + d^{10} e^{4} x + d^{11} e^{3}\right )}} \]
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Time = 0.82 (sec) , antiderivative size = 321, normalized size of antiderivative = 1.71 \[ \int \frac {(f+g x)^2}{(d+e x) \left (d^2-e^2 x^2\right )^3} \, dx=- \frac {- 4 d^{6} g^{2} - 16 d^{5} e f g + 8 d^{4} e^{2} f^{2} + x^{4} \left (- 3 d^{2} e^{4} g^{2} + 6 d e^{5} f g + 15 e^{6} f^{2}\right ) + x^{3} \left (- 3 d^{3} e^{3} g^{2} + 6 d^{2} e^{4} f g + 15 d e^{5} f^{2}\right ) + x^{2} \cdot \left (5 d^{4} e^{2} g^{2} - 10 d^{3} e^{3} f g - 25 d^{2} e^{4} f^{2}\right ) + x \left (- 7 d^{5} e g^{2} - 10 d^{4} e^{2} f g - 25 d^{3} e^{3} f^{2}\right )}{48 d^{10} e^{3} + 48 d^{9} e^{4} x - 96 d^{8} e^{5} x^{2} - 96 d^{7} e^{6} x^{3} + 48 d^{6} e^{7} x^{4} + 48 d^{5} e^{8} x^{5}} + \frac {\left (d^{2} g^{2} - 2 d e f g - 5 e^{2} f^{2}\right ) \log {\left (- \frac {d}{e} + x \right )}}{32 d^{6} e^{3}} - \frac {\left (d^{2} g^{2} - 2 d e f g - 5 e^{2} f^{2}\right ) \log {\left (\frac {d}{e} + x \right )}}{32 d^{6} e^{3}} \]
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Time = 0.19 (sec) , antiderivative size = 308, normalized size of antiderivative = 1.64 \[ \int \frac {(f+g x)^2}{(d+e x) \left (d^2-e^2 x^2\right )^3} \, dx=-\frac {8 \, d^{4} e^{2} f^{2} - 16 \, d^{5} e f g - 4 \, d^{6} g^{2} + 3 \, {\left (5 \, e^{6} f^{2} + 2 \, d e^{5} f g - d^{2} e^{4} g^{2}\right )} x^{4} + 3 \, {\left (5 \, d e^{5} f^{2} + 2 \, d^{2} e^{4} f g - d^{3} e^{3} g^{2}\right )} x^{3} - 5 \, {\left (5 \, d^{2} e^{4} f^{2} + 2 \, d^{3} e^{3} f g - d^{4} e^{2} g^{2}\right )} x^{2} - {\left (25 \, d^{3} e^{3} f^{2} + 10 \, d^{4} e^{2} f g + 7 \, d^{5} e g^{2}\right )} x}{48 \, {\left (d^{5} e^{8} x^{5} + d^{6} e^{7} x^{4} - 2 \, d^{7} e^{6} x^{3} - 2 \, d^{8} e^{5} x^{2} + d^{9} e^{4} x + d^{10} e^{3}\right )}} + \frac {{\left (5 \, e^{2} f^{2} + 2 \, d e f g - d^{2} g^{2}\right )} \log \left (e x + d\right )}{32 \, d^{6} e^{3}} - \frac {{\left (5 \, e^{2} f^{2} + 2 \, d e f g - d^{2} g^{2}\right )} \log \left (e x - d\right )}{32 \, d^{6} e^{3}} \]
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Time = 0.28 (sec) , antiderivative size = 277, normalized size of antiderivative = 1.47 \[ \int \frac {(f+g x)^2}{(d+e x) \left (d^2-e^2 x^2\right )^3} \, dx=\frac {{\left (5 \, e^{2} f^{2} + 2 \, d e f g - d^{2} g^{2}\right )} \log \left ({\left | e x + d \right |}\right )}{32 \, d^{6} e^{3}} - \frac {{\left (5 \, e^{2} f^{2} + 2 \, d e f g - d^{2} g^{2}\right )} \log \left ({\left | e x - d \right |}\right )}{32 \, d^{6} e^{3}} - \frac {8 \, d^{5} e^{2} f^{2} - 16 \, d^{6} e f g - 4 \, d^{7} g^{2} + 3 \, {\left (5 \, d e^{6} f^{2} + 2 \, d^{2} e^{5} f g - d^{3} e^{4} g^{2}\right )} x^{4} + 3 \, {\left (5 \, d^{2} e^{5} f^{2} + 2 \, d^{3} e^{4} f g - d^{4} e^{3} g^{2}\right )} x^{3} - 5 \, {\left (5 \, d^{3} e^{4} f^{2} + 2 \, d^{4} e^{3} f g - d^{5} e^{2} g^{2}\right )} x^{2} - {\left (25 \, d^{4} e^{3} f^{2} + 10 \, d^{5} e^{2} f g + 7 \, d^{6} e g^{2}\right )} x}{48 \, {\left (e x + d\right )}^{3} {\left (e x - d\right )}^{2} d^{6} e^{3}} \]
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Time = 11.80 (sec) , antiderivative size = 249, normalized size of antiderivative = 1.32 \[ \int \frac {(f+g x)^2}{(d+e x) \left (d^2-e^2 x^2\right )^3} \, dx=\frac {\frac {d^2\,g^2+4\,d\,e\,f\,g-2\,e^2\,f^2}{12\,d\,e^3}-\frac {x^3\,\left (-d^2\,g^2+2\,d\,e\,f\,g+5\,e^2\,f^2\right )}{16\,d^4}-\frac {e\,x^4\,\left (-d^2\,g^2+2\,d\,e\,f\,g+5\,e^2\,f^2\right )}{16\,d^5}+\frac {x\,\left (7\,d^2\,g^2+10\,d\,e\,f\,g+25\,e^2\,f^2\right )}{48\,d^2\,e^2}+\frac {5\,x^2\,\left (-d^2\,g^2+2\,d\,e\,f\,g+5\,e^2\,f^2\right )}{48\,d^3\,e}}{d^5+d^4\,e\,x-2\,d^3\,e^2\,x^2-2\,d^2\,e^3\,x^3+d\,e^4\,x^4+e^5\,x^5}+\frac {\mathrm {atanh}\left (\frac {e\,x}{d}\right )\,\left (-d^2\,g^2+2\,d\,e\,f\,g+5\,e^2\,f^2\right )}{16\,d^6\,e^3} \]
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